旧博客原文
原题:Analysis Qualifying Examination(UCLA 2009)
1.
Let be real-valued integrable functions on a measure space
,and define:
.
Prove:
.
proof:
by Fubini theorem(cake representation theorem in fact):
.
(there is a geometric heuristic,strict proof is due to fubini theorem)
Q.E.D.
2.
Let be a infinite dimensional real Hilbert space.
a)Prove the unit sphere of
is weakly dense in the unit ball
of
.
b)Prove there is a sequence of bounded linear operator from
to
such that
for all n but
for all
.
proof:
by Zorn lemma there is a orthogonal bases .
to proof a),suffice to proof:.
this can be done by look at the expansion .due to the Cauchy inequality,there is a freedom of choice the coefficient
for
.the choice will lead a).
b) is trivial due to a).
Q.E.D.
3.Let be a Banach space and let $X^*$ be it dual Banach space.Prove that if
is separable then
is separable.
proof:
we know is the space consist with bounded(continued) linear functional on
.
for ,
,so due to
is separable.there is a countable dense set
in
.i.e.
.we equip a member of
to
by
,
.
On the other hand, we construct a functional
.
.so it is obviously to show
is dense in
.
Q.E.D.
5.Let be the unit interval,and for
and
,let:
.
For define
.
Prove that if then
a.e. in I.
proof:
…gap…
10.Let be the open unit disc and
be Lebesgue measure on
.let
be the subspace of
consisting of holomorphic functions.Show that
is complete.
proof:maximum norm principle.to show is closed uniformly coverage.so is harmonic and
is due to
itself is complete.
Q.E.D.
补充说明
以下是新整理的中文说明;上方旧博客原文保持不变。
这组题表面上分散:有测度论、Hilbert 空间弱拓扑、Banach 空间可分性、函数空间闭性。但它们的共同核心是:把抽象对象转化为可数逼近、积分层分解或闭性问题。

1. Layer-cake 与 Fubini
对非负函数 $f$,常用恒等式是
$$f(x)=\int_0^\infty \mathbf 1_{\{f(x)>t\}}\,dt.$$
积分后用 Fubini 交换次序,就得到 layer-cake representation。很多看似是范数不等式的题,其实都可以化成集合层面的包含关系。
2. Hilbert 空间单位球的弱拓扑
在无限维 Hilbert 空间中,单位球的弱闭包现象和强拓扑非常不同。给定 $\|x\|\le1$,可以在与有限多个测试向量正交的方向上添加一个小向量,使范数变成 $1$,同时不改变这些测试函数的值。于是单位球中的点可被单位球面弱逼近。
3. 可分性与对偶
若 $X^*$ 可分,则 $X$ 可分。证明思路是从 $X^*$ 中取可数稠密集 $\{f_n\}$,再为每个有限线性条件选择近似达到范数的点。Hahn-Banach 的思想隐藏在这里:对偶空间的可数信息足以区分 $X$ 中的点。
4. 闭子空间的完备性
若 $L^2(D)$ 中的全纯函数子空间在 $L^2$ 收敛下保持全纯,那么它就是闭子空间,从而完备。关键是用局部估计把 $L^2$ 收敛提升为紧子集上的一致收敛,再由 Weierstrass 定理保全全纯性。