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  • 奇异积分一般理论一瞥:近似恒等、Fourier multiplier 与 square function

    旧博客原文

    原题:A glimpse to the general theory

    1. Introduction

    We have talked about a very basic result in singular integral, i.e. if we have an additional condition, i.e. {q-q} bounded condition, then by interpolation theorem we only need to establish the weak {1-1} bound then we establish the {p-p} bound of {T}, {\forall 1< p< q }.

    The category of of singular integral is very general, in fact the singular integral we interested in always equipped more special structure. We discuss following 3 types result which world be the central role in this further series note.

    1. Approximation of the identity.
    2. Singular integral with {L^2} bounded translation invariant operator.
    3. Maximal function, singular integral, and square functions.

    The underlying object we consider in both the three case is some special singular integral, in the first case, it looks like a {T=sup_{t>0} \Phi_{t}*f}, this, among the other thing, has a close relationship with the maximal operator {Mf}. This is discussed in 2. For the singular integral with {L^2} bound, the Fourier transform or its discretization version, Fourier series is natural involved. And there is a “representation theorem” similar to the sprite of Reisz representation theorem, said, roughly speaking, if we consider the {L^2} bound operator adding the condition of transform invariant, then it is really coinside with the case of our image, the operator must behaviour as a Fourier multiple. This is the contant of famous Mikhlin multiplier theorem, and we discuss some technique difficulty in the process of establishing such a theorem, this is the contact of 3. At last we discuss some deep relationship between three basic underlying intution and objects in harmonica analysis, the Maximal function, singular integral, and square functions. They could all be understanding as tools to understanding the variant complicated emerging in singular integral. But there is definitely some common points. This is the theme of 4. Of course there are some further topic which are also interesting, but I do not want to discuss them here, maybe somewhere else.

    2. Approximation of the identity

    First topic, we discuss the approximation of the identity, this play a central role in understanding solution of PDE, why, I think a key point is this tools carry a lots of information about the scaling of the space, as it well known, analysis could roughly divide into two parts, “hard analysis” and “soft analysis”, approximation of the identity supply a way to transform a result form “hard analysis” side to “soft analysis” side and reverse. And when it shows its whole power always along with the involving of following Dominate convergence theorem:

    Theorem 1 (DCT)

    Let {\{f_n\}_{n=1}^{\infty}} be a series of function on measure space {(X,\Sigma,\mu)}, and {f_n \rightarrow f, a.e. x\in X}, and {\{f_n\}_{n=1}^{\infty}} satisfied a controlling condition, i.e. we can find a integrable function {g\in L^{1}(X)}, such that {|f_n(x)|\leq |g(x)|, a.e. x\in X, \forall n\in {\mathbb N}^*}, then we know,

    \displaystyle \lim_{n\rightarrow \infty} \int_{X}f_n(x)d\mu\rightarrow \int f(x)d\mu \ \ \ \ \ (1)

     

    In fact we have even stronger,

    \displaystyle \lim_{n\rightarrow \infty} \int_{X}|f_n(x)-f(x)|d\mu=0 \ \ \ \ \ (2)

     

    This is a standard theorem in real analysis, we give the proof.

    Proof: {f} is the point-wise limit of {f_n} so we know f is measurable and also dominate by {g}, so by triangle inequality we have:

    \displaystyle |f-f_n|\leq 2|g|

    Then the 1 is trivially true, due to a diagonal taking subsequences trick. For more subtle result 2, we need use reverse Fatou theorem to show it is true, roughly speaking we have,

    \displaystyle \limsup_{n\rightarrow \infty}\int_{X}|f_n-f|\leq \int_{X}\limsup_{n\rightarrow \infty}|f_n-f|=0

    The key point is the first inequality above used the reverse Fatou theorem. \Box

    Now we discuss of the main result of the approximation identity. So first we need to define what is a approximation identity. a key ingredient is scaling. i.e. we given a function {\Phi} and consider {\Phi_t=t^{-n}\Phi(\frac{x}{t})}, and we wish,

    \displaystyle \lim_{t\rightarrow 0}(f*\Phi_t(x))=f(x), for a.e. x\ \in {\mathbb R}^n \ \ \ \ \ (3)

     

    Whenever {f\in L^p, 1\leq p\leq \infty}, but there need some technique assume to make this intuition to be tight, this lead the following definition.

    Definition 2 (Approximation of the identity) Suppose {\Phi} is a fixed function on {{\mathbb R}^n} that is appropriated small at infinity (have good enough decay rate), for example, take,

    \displaystyle |\Phi(x)|\leq A(1+|x|)^{-n-\epsilon} \ \ \ \ \ (4)

     

    Then we define {\{\Phi_t:\Phi_t(x)=t^{-n}\Phi(\frac{x}{t})\}} to be an approximation of the identity.

    The key theorem is the following, related the approximation of the indentity with the maximal operator.

    Theorem 3

    \displaystyle \sup_{t>0}|(\Phi_t*f)(x)|\leq c_{\Phi}Mf(x) \ \ \ \ \ (5)

     

    For heat kernel, the thing is more subtle.

    Theorem 4 [Heat kernel estimate]

    \displaystyle \|f-e^{t\Delta}f\|_2\leq \|\nabla f\|_2\sqrt{t} \ \ \ \ \ (6)

     

    Remark 1 I know this theorem from Lieb’s book. The power of 4 combine with Plancherel theorem could use to establish the Sobolev inequality, at least for the index {p=2}.

    There are 3 ingredients which cold be useful.

    1. the power of Rearrangement inequality involve in the Approximation of indentity operator. we could consider the relationship between {f*\Phi_t} and {f*\overline \Phi_t}, where {\overline \Phi} is constructed by take the average of {\Phi} on the level set but the foliation of scaling. Intuition seems some monotonic property natural emerge.
    2. There is a discretization model, i.e. the toy model on gragh, or we think it as correlation between particles, the key point is the rescaling deformation could be instead by semi group or renormalization property.
    3. We consider the more general case, now there is not only one {\Phi} but a group of them, i.e. {\Phi_k, k\in A}, this will involve some amenable theory I think.

    We give two of the original and most important examples, First, if

    \displaystyle \Phi(x)=c_n(1+|x|^2)^{\frac{-(n+1)}{2}}

    where

    \displaystyle c_n=\frac{\Gamma(\frac{n+1}{2})}{\pi^{\frac{n+1}{2}}}

    then {\Phi_t(x)} is the possion kernel, and,

    \displaystyle u(x,t)=(f*\Phi_t)(x)

    Gives the solution of the Dirichlet problem for the upper half space,

    \displaystyle {\mathbb R}^{n+1}_{+}=\{(x,t):x\in {\mathbb R}^n,t>0\}

    Namely

    \displaystyle \Delta u=(\frac{\partial^2}{\partial t^2}+ \sum_{j=1}^n\frac{\partial^2}{\partial x_j^2})u(x,t)=0,\ u(x,0)\equiv f(x) \ \ \ \ \ (7)

     

    The second example is the Gaussian kernel,

    \displaystyle \Phi(x)=(4\pi)^{-\frac{n}{2}}e^{-\frac{|x|^2}{4}}.

    This time, if {u(x,t)=(f*\Phi_{t^{\frac{1}{2}}})(x)}, then {u} is a solution of the heat equation,

    \displaystyle (\frac{\partial}{\partial t}- \sum_{j=1}^n\frac{\partial^2}{\partial x_j^2})u(x,t)=0,\ u(x,0)\equiv f(x) \ \ \ \ \ (8)

     

     

    3. Singular integral with {L^2} bounded translation invariant operator

    The main result proved in last note about singular integral is a conditional one, guaranteeing the boundedness on {L^p} for a range {1<p\leq q}, on the assupution that the boundedness on {L^q} is already known; the most important instance of this occurs when {q=2}. In keeping with this, we consider bounded linear transformation {T} from {L^2({\mathbb R}^n)} to itself that commute with translation. As is well known, such operator are characterized by the existence of a bounded function {m} on {{\mathbb R}^n} (the “multiper”), so that {T} can be realized as,

    \displaystyle \widehat{Tf(\xi)}=m(\xi)\widehat f(\xi) \ \ \ \ \ (9)

    Where {\widehat{}} denotes the Fourier transform. Alternatively, at least on test function {f\in S}, {T} can be realized in terms of convolution with a kernel {K},

    \displaystyle Tf=f*K \ \ \ \ \ (10)

     

    Where {K} is the distribution given by {\hat K=m}. We shall now examine how the theorem with condition on singular integral weill lead to some result of this type of operator. Roughly speaking, it is due to now we know the boundedness on {L^2}, for technique condition, we need to assume the distribution {K} agree away from the origin with a function that is locally integrable away from the origin with a function that is locally integrable away from the origin; in this case we define the function by {K(x)}. Then 10 implies that,

    \displaystyle Tf(x)=\int K(x-y)f(y)dy,\ for \ a.e. x\notin supp f. \ \ \ \ \ (11)

    Whenever {f} is in {L^2} and {f} has campact support. Tis is the representation of singular integral in the present context. Next, the crucial hormander condition is then equivalent with,

    \displaystyle \int_{|x|\geq c|y|}|K(x-y)-K(x)|dx\leq A \ \ \ \ \ (12)

     

    for all {y\neq 0}, where {c>1}. In this case, the condition 12 have a further understanding, in fact,

    Lemma 5

    \displaystyle |(\frac{\partial}{\partial x}^{\alpha}K(x))|\leq A_{\alpha}|x|^{-n-|\alpha|},\ for\ all \ \ \alpha \ \ \ \ \ (13)

     

    or its weaker form, (here {\gamma>0} is fixed )

    \displaystyle |K(x-y)-K()|\leq A\frac{|y|^{\gamma}}{|x|^{n+\gamma}}, whenever \ |x|\geq c|y|. \ \ \ \ \ (14)

    imply the hormander condition 12

    Proof: Integral by part. \Box

    So, now the key point is how do {K}, satisfied such conditions, come about? It turns out that, toughly speaking, such condition on {K} have equivalent versions when sated in terms of the Fourier transform of {K}, namely the multiper {m}. This is transform the difficulties from physics space to fractional space In the future note, we will find a proof of the following Theorem:

    Theorem 6 For {m=\hat K}.

    If we assume that,

    \displaystyle |(\frac{\partial}{\partial \xi}^{\alpha}m(\xi))|\leq A'_{\alpha}|\xi|^{-n-|\alpha|},\ for\ all \ \ \alpha \ \ \ \ \ (15)

    holds for all {\alpha}, then {K} satisfied 5 for all {\alpha}.

    If we assume that {m} satisfied the above inequality for all {0\leq |\alpha| \leq l}, where {l} is the smallest integer {>\frac{n}{2}}, then {K} satisfied 12

    Remark 2 The multiplier {m} satisfied the second part condition of 6, are called Marcinkiewicz mulltiplier.

     

    4. Maximal function, singular integral, and square functions.

     


    补充说明

    以下是新整理的中文说明;上方旧博客原文保持不变。

    奇异积分的基本理论不只是 Calderon-Zygmund 分解。真正进入一般理论以后,会反复出现三类对象:approximation of the identity、translation invariant singular integrals,也就是 Fourier multipliers,以及 maximal function 和 square function。

    奇异积分一般理论一瞥:近似恒等、Fourier multiplier 与 square function
    奇异积分一般理论中,近似恒等、Fourier multiplier 和 square function 分别控制尺度极限、平移不变结构和多尺度正交性。

    1. 从弱型估计到 $L^p$ 有界性

    如果一个奇异积分算子 $T$ 已知在 $L^2$ 上有界,并且满足弱 $(1,1)$ 估计

    $$|\{x:|Tf(x)|>\lambda\}|\lesssim \frac{\|f\|_1}{\lambda},$$

    那么 Marcinkiewicz interpolation 给出 $1

    2. Approximation of the identity

    取一族核 $\phi_t(x)=t^{-n}\phi(x/t)$,若 $\int\phi=1$,则

    $$\phi_t*f\to f\quad(t\to0).$$

    这类算子看起来温和,但它们和 maximal operator 紧密相连。控制

    $$\sup_{t>0}|\phi_t*f(x)|$$

    本质上就是控制函数在不同尺度上的平均行为。

    3. Translation invariant operators

    若 $T$ 与平移可交换,那么 Fourier transform 会把它对角化:

    $$\widehat{Tf}(\xi)=m(\xi)\widehat f(\xi).$$

    Mikhlin multiplier theorem 给出一套可检验条件:若

    $$|\partial^\alpha m(\xi)|\lesssim |\xi|^{-|\alpha|}$$

    到足够阶数成立,则 $T$ 在 $L^p$ 上有界。

    4. Square functions

    square function 把函数分解到不同频率或尺度:

    $$Sf(x)=\left(\sum_j |P_jf(x)|^2\right)^{1/2}.$$

    它不是只估计每一块,而是用正交性追踪所有尺度的总能量。这是 Littlewood-Paley 理论的核心。

    5. 一条总线

    近似恒等处理尺度极限,multiplier theory 处理平移不变结构,square function 处理多尺度正交性。奇异积分的一般理论,就是在这三种结构之间来回切换。

  • Sturm-Liouville theory 与周期轨道:谱分解、边界条件和 monodromy

    旧博客原文

    原题:Periodic orbits and Sturm–Liouville theory

    I thinks there is some problem related to the solution of a 2 order differential equation given by Sturm-Liouville system which is nontrivial.

    It is well-know that the power of Sturm-Liouville theory see  wiki, is due to it is some kind of “spectral decomposition” in the solution space.

    Two kind of problem is interesting, one is the eigenvalue estimate, both upper bound and lower bound, this already investigated in ESTIMATING THE EIGENVALUES OF STURM-LIOUVILLE. PROBLEMS BY APPROXIMATING THE DIFFERENTIAL EQUATION.

    I post two problem here, this is a product due to a random walk along the boundary of topology and the analysis,

    Problem 1.

    Fix a set A=\{k_1<k_2<...<k_l\}, is there a 2 order ordinary differential equation given by Sturm–Liouville theory  such that the eigenfunction f_{k} is periodic if and only if k\in A?

    There is also some weak version of this and a infinity version of this.

    Of course we have the following map, from the high order ordinary differential equation to the 1 order differential equation in high dimension. But the key point is that it is not a bijection! The Frobenius condition play a crucial role.

    Problem 2.

    There is a homotopy in the moduli space of differential equation, and we could define a direct product operator in this space, and we consider the topology defamation of the eigenfunction, could there be some equality, one side of it explain the topology information, the other side explain the spectral (or analysis) information?

    There is another interesting problem.


    补充说明

    以下是新整理的中文说明;上方旧博客原文保持不变。

    Sturm-Liouville theory 把二阶线性微分方程变成谱问题。若再加入周期边界条件,就会自然出现 monodromy matrix、周期解和一维动力系统的交界。

    Sturm-Liouville theory 与周期轨道:谱分解、边界条件和 monodromy
    Sturm-Liouville 周期谱可以通过一阶系统的 monodromy matrix 来刻画。

    1. Sturm-Liouville 系统

    标准形式为

    $$-(p(x)y’)’+q(x)y=\lambda w(x)y.$$

    在合适边界条件下,这是自伴特征值问题,特征函数构成正交基。

    2. 周期边界条件

    若区间为 $[0,T]$,周期解满足

    $$y(0)=y(T),\qquad y'(0)=y'(T).$$

    这等价于一阶系统的 monodromy matrix 有特征值 $1$。

    3. 从二阶到一阶系统

    令 $Y=(y,py’)$,二阶方程可写为

    $$Y’=A_\lambda(x)Y.$$

    基本解矩阵 $M_\lambda(T)$ 描述一个周期后的变化。周期谱由

    $$\det(M_\lambda(T)-I)=0$$

    刻画。

    4. 反问题

    一个自然问题是:能否指定某个集合 $S$,使得周期特征值恰好落在 $S$ 中?这类问题接近 inverse spectral theory,需要理解势函数 $q(x)$ 如何控制 monodromy。

    5. 拓扑与分析

    周期轨道是动力系统对象,Sturm-Liouville 是谱分析对象。monodromy matrix 把二者联系起来:谱参数变化时,monodromy 在矩阵群中运动,周期解对应它穿过特定子集。

  • Calderon-Zygmund 分解:奇异积分的实变量入口

    旧博客原文

    原题:Calderon-Zygmund theory of singular integrals.

    1. Calderon-Zygmund decomposition

    The Calderon-Zygmund decomposition is a key step in the real variable analysis of singular integrals. The idea behind this decomposition is that it is often useful to split an arbitrary integrable function into its “small” and “large” parts, and then use different technique to analyze each part.

    The scheme is roughly as follows. Given a unction { f} and an altitude { \alpha}, we write { f=g+b}, where { |g|} is point wise bounded by a constant multiple {\alpha}. While { b} is large, it does enjoy two redeeming features: it is supported in a set of reasonable small measure, and its mean value is zero on each of the ball that constitute its support. To obtain the decomposition { f=g+b}, one might be tempted to “cut” { f} at the height { \alpha}; however, this is not what works. Instead, one bases the composition on the set where the maximal function of { f}has height { \alpha}.

    Theorem 1 (Calderon-Zygmund decomposition)

    Suppose we are given a function { f\in L^1} and a positive number { \alpha}, with {\alpha>\frac{1}{\mu(R^n)}\int_{R^n}|f|d\mu}. Then there exists a decomposition of { f}, {f=g+b}, with { b=\sum_{k}b_k}, and a sequences of balls {\{B_k^*\}}, so that,

    1. { |g(x)|\leq c\alpha}, for a.e. { x}.
    2. Each {latex b_k} is supported in {B_k^*},{ \int|b_k(x)|d\mu(x)\leq c\alpha\mu(B_k^*)}, and { \int b_k(x)d\mu(x)=0}.
    3. { \sum_k\mu(B_k^*)\leq \frac{c}{\alpha}\int|f(x)|d\mu(x)}.

     

    Before proof this theorem, I explain the geometric intuition why this theorem could be true first. Merely speaking, this is just base on cut off the function into two part, the part with high altitude and the part with low altitude and extension the part with high altitude to make the extension one satisfied the condition 2 and 3.

    Proof: In fact this decomposition have a good geometric explain, we just divide the part {\{x: |f(x)|>\alpha\}} and extension it carefully to make they behaviour like several balls, to satisfied the special condition on this part. \Box

    Remark 1 Remark 1: A Calderon-Zygmund decomposition for {L^p} function was done in Charlie Fefferman’s thesis; see Section II of ams.org/mathscinet-getitem?mr=257819  One can also find this in Loukas Grafakos’s Classical Fourier Analysis Classical Fourier Analysis page 303 exercise 4.3.8. The question is broken up into parts that should be easy to handle.

    Several people have considered with this question. An excellent paper that comes to mind is Anthony Carbery’s Variants of the Calderon–Zygmund theory for { L^p}-spaces which appeared in Revista Matematica Iberoamericana, Volume 2, Number 4 in 1986. There are also several useful references that appear in Carbery’s paper.

    Remark 2 We could also consider a variant of Calderon-Zygmund decomposition, such as equipped with a nontrivial weight function { w} or find some different way to decomposition for some special purpose.

    Remark 3 Consider suitable decomposition of the physics space or even both the physics space and fractional space try to gain some reasonable estimate is a fundamental philosophy in harmonic analysis, beside the Calderon-Zegmund decomposition,

    Whitney decomposition. Which is important trick in the proof of fefferman-stein restriction theorem and differential topology.

    Wave packet decomposition. The wave packet decomposition. This decomposition underlies the proof of Carleson’s theorem (this is more explicit in Fefferman’s proof than Carelson’s original proof), Lacey and Thiele’s proof of the boundedness of the bilinear Hilbert transform, as well as a host of follow-up work in multilinear harmonic analysis. The idea of the wave packet decomposition is to decompose a function/operator in terms of an overdetermined basis. This allows one to preserve symmetries (such as modulation symmetries) that aren’t preserved by a classical Calderon-Zygmund decomposition (which endows the frequency with a distinguished role). One might consider using a wave packet decomposition if is working with an operator that has a modulation symmetry. This is discussed in more detailed in Tao’s blog post on the trilinear Hilbert transform.

    Polynomial decomposition. The application of polynomial decomposition to harmonic analysis is more recent, and its full potential still seems unclear. Applications include Dvir’s proof of the finite field Kakeya conjecture, Guth’s proof of the endpoint multilinear Kakeya conjecture (and, indirectly, the Bourgain-Guth restriction theorems), Katz and Guth’s proof of the joints problem and Erdos distance problem, among many other results. Generally, the idea behind the polynomial decomposition is to partition a subset of a vector space over a field into a finite number of cells each of which contains roughly the same fraction of the original set. One further wishes that no low degree algebraic variety can intersect too many of the cells. In Euclidean space, the polynomial ham sandwich decomposition does exactly this. This allows one to, for instance, control linear (or, more generally, `low algebraic degree’) interactions between points in distinct cells. This has so far proven the most useful in incidence-type problems, but many problems in harmonic analysis, thanks to the translation symmetry of the Fourier transform, are inextricably linked with such incidence-type problems. See (again) Tao’s survey of this topic for a more detailed account.

     

    2. Singular integrals

    Have the Calderon-Zegmund decomposition in hand, now we proof a conditional one bounded result for singular integrals.

    The singular integral one is interested in are operator { T}, expressible in the form

    \displaystyle (Tf)(x)=\int_{R^n}K(x,y)f(y)d\mu(y) \ \ \ \ \ (1)

     

    Where the kernel { K} is singular near { x=y}, and so the expression is meaningful only if { K} is treated as a distribution or in some limiting sense. Now the particular regularization of { (Tf)(x)} may be appropriate depends much on the context, and a complete treatment of the issues thereby raised take us quite far afield.

    Let us limit ourselves to two closely related ways of dealing with the questions concerning the definability of the operator. One is to prove estimates for the (dense) subspace where the operator is initially defined. The other is to regularize the given operators by replacing it with a suitable family, and to prove the uniformly estimates for this family. This idea is similar occurring in spectral geometry when we wish to investigate the spectrum of some operator we try to consider some deformation, so deduce to control the spectrum of a seres of paramatrix, for example, consider the wave kernel or heat kernel rather than the passion kernel itself. Common to both methods is a priori approach: We assume some additional properties of the kernel, but then prove estimates that are independent of these “regularity” properties.

    We now carry out the first approach in detail. There will be two kinds of assumptions made about the operator. The first is quantitative: we assume that we are given a bound { A}, so that the operator { T} is defined and bounded on { L^q} with norm { A}; that is,

    \displaystyle \|T(f)\|_q\leq A\|f\|_q, \forall f, f\in L^q \ \ \ \ \ (2)

     

    Moreover, we assume that there is associated to { T} a measurable function { K} (that plays the role of its kernel), so that for the same constant { A} and some constant { c>1},

    \displaystyle \int_{R^n-B(y,c\delta)}|K(x,y)-K(x,\bar y)|d\mu(x)\leq A, \forall \bar y\in B(y,\delta)  \ \ \ \ \ (3)

     

    for all { y\in R^n, \delta>0}.

    The further regularity assumption on the kernel { K} is that for each { f} in {L^q} that has compact surppot, the integral coverages absolutely for almost all { x } in the complement of the support of { f}, and that equality holds for these { x}.

    Theorem 2 (Bounded of singular integral with condition)

    Under the condition 1 and 3 made above on { K}, the operator { T} is bounded in { L^p} norm on { L^p\cap L^q}, when { 1<p<q}. More precisely,

    \displaystyle \|T(f)\|_p\leq A_p\|f\|_p

    For { f\in L^p\cap L^q} with { 1<p<q}, where the bound { A_p} depends only on the constant { A} appearing in 1 and 3 and on { p}, but not on the assumed regularity of { K}, or on { f}.

     

    Proof:

    Now let us begin to prove the conditional theorem. The key point is to use the potential of {T} has been a bounded operator from {L^q\rightarrow L^q}. Said, it already assumed {\exists A>0} such that {\forall f\in L^q} we have {\|T(f)\|_q\leq A\|f\|_q}. Now let us look at the singular integral expression:

    \displaystyle (Tf)(x)=\int_{R^n}K(x,y)f(y)d\mu(y). \ \ \ \ \ (4)

     

     

    The key point is to proof the mapping {f\rightarrow T(f)} is a weak-type {1-1}; that is,

    \displaystyle \mu\{x:|Tf(x)|>\alpha\}\leq \frac{A'}{\alpha}\int |f|d\mu. \ \ \ \ \ (5)

     

    At once we establish 5, then the theorem followed by interpolation. Now we use theorem 1 on {f} get {f=g+b}, thanks to the triangle inequality and something similar we have {g,b \in L^q}, in fact {R^n= A\amalg B, B\cup_{k}B_k}, {g=\chi_A g+\chi_{B}g, b=\chi_A b+\chi_{B} b}, by triangle inequality and {f=g+b}, to proof {g,b \in L^q}, we only need to proof {\chi_A g, \chi_B g, \chi_A b, \chi_B b\in L^q}, but this is easy to proof.

    Now we know the {L^q} bounded of {g,b}, we divide the difficult of establish the weak 1-1 bound of {f} into the difficult of establish the weak 1-1 bound for {g} and {b}. i.e.

    \displaystyle \mu\{x:|Tf(x)|>\alpha\}\leq \mu \{x:|Tg(x)|>\alpha\} +\mu\{x:|Tb(x)|>\alpha\} \ \ \ \ \ (6)

     

    For {g}, if this weak 1-1 bound is not true, we have,

    \displaystyle \mu \{x:|Tg(x)|>\alpha\}\geq \frac{A'}{\alpha}\int |g|d\mu \ \ \ \ \ (7)

     

    thanks to the trivial estimate {\|g\|_q \leq c\alpha^{q-1}\|g\|_1 }. combine this two estimate we have:

    \displaystyle c\alpha^{q-1}\|g\|_1\geq \|g\|^q_q\geq c\|Tg\|^q_q \geq A'\alpha^{q-1} \|g\|_1 \ \ \ \ \ (8)

     

    The first estimate is true on {A} due to {|g|\leq \alpha, a.e. x\in R^n}. But compare the left and the right of 8 lead a contradiction, so 7 follows. For {b}, the thing is more complicated and in fact really involve the structure of the convolution type of the singular integral. The key point is controlling near the diagonal of {K(x,y)}. we warm up with a more refine decomposition {b=\sum b_k}, {\forall k, b_k=b\cdot \chi_{B_k}}. For a large constant {c>>1} choose later define {B^*_k=c B_k}. We know {b\in L^q}, but the really difficult thing occur in the how to combine the following 5 condition to lead a contradiction:

    1. {\|Tb\|_q\leq \|b\|_q}.
    2. property come from the Calderon-Zegmund decomposition, {\int_{B_k}\|b\|\leq c\alpha \mu(B_k),\forall k} and {\int_{B_k}b=0}.
    3. Hormander condition 3 , {\int_{R^n-B(y,c\delta)}|K(x,y)-K(x,\bar y)|d\mu(x)\leq A, \forall \bar y\in B(y,\delta)}
    4. the reverse of weak 1-1 of {b}, {\mu\{x:b(x)>\alpha\}> \frac{A'}{\alpha}\|b\|_1}.
    5. the structure {Tb(x)=\int_{R^n} K(x,y)b(y)dy}

    The first step is to break {b} into {b_k}, and reduce the case of several balls to the case of only one ball, this could be done by triangle inequality or more may be we could do it derectly, but any way it is not difficult.

    Then the thing become intersting, we focus on {b_1}, divide {Tb_1=T\chi_{B_1} b_1+ T\chi_{{\mathbb R}^n-B_1}b}. thanks to the hormander condition 3 we have good control on {T\chi_{{\mathbb R}^n-B_1^*}}, in fact we can proof a weak 1-1 bound on it,

    \displaystyle \mu\{x:|T_{{\mathbb R}^n-B_1^*}b_1|>\alpha\}< \frac{A'}{\alpha}\|b_1\|_1 \ \ \ \ \ (9)

    \displaystyle \begin{array}{rcl} T_{{\mathbb R}^n-B_1^*}b_1(x) & = & \int_{{\mathbb R}^n-B_1^*}K(x,y)b_1(y)dy\\ & = & \int_{{\mathbb R}^n-B_1^*}[K(x,y)-K(x,\bar y)]b_1(y)dy+\int_{{\mathbb R}^n-B_1^*}K(x,\bar y)b_1(y)dy\\ & \leq & \int_{{\mathbb R}^n-B_1^*}Ab_1(y)dy+\int_{{\mathbb R}^n-B_1^*}K(x,\bar y)b_1(y)dy \end{array}

    So we conclude,

    \displaystyle \begin{array}{rcl} \|T_{{\mathbb R}^n-B_1^*}b_1\|_1 & = & \int_{{\mathbb R}^n}|\int_{{\mathbb R}^n-B_1^*}K(x,y)b_1(y)dy|dx\\ & = & \int_{{\mathbb R}^n}\int_{{\mathbb R}^n-B_1^*}|[K(x,y)-K(x,\bar y)]b_1(y)dy|dx+\int_{{\mathbb R}^n}|\int_{{\mathbb R}^n-B_1^*}K(x,\bar y)b_1(y)dy|dx\\ & \leq & A\int_{{\mathbb R}^n}b_1(y)dy+\int_{{\mathbb R}^n-B_1^*}K(x,\bar y)b_1(y)dy=A\int_{{\mathbb R}^n}b_1(y)dy \end{array}

    The last equality used the condition {\int b_1=0}.

    \Box

     


    补充说明

    以下是新整理的中文说明;上方旧博客原文保持不变。

    Calderon-Zygmund 分解是实变量调和分析里最基本的动作之一。它不是简单地把函数按高度截断,而是用 Hardy-Littlewood maximal function 找到真正危险的区域,再把函数分成一个有界的好部分和一族有 cancellation 的坏部分。

    Calderon-Zygmund 分解:奇异积分的实变量入口
    Calderon-Zygmund 分解用 maximal function 找到坏区域,把函数拆成有界部分和带 cancellation 的局部坏块。

    1. 为什么不能直接截断

    给定 $f\in L^1(\mathbb R^n)$ 和高度 $\lambda>0$,我们希望写成

    $$f=g+\sum_j b_j.$$

    其中 $g$ 应该满足 $|g|\lesssim \lambda$,而 $b_j$ 虽然可能很大,但支撑在小集合上,并且有零平均。直接令 $g=f\mathbf 1_{\{|f|\le \lambda\}}$ 并不够,因为奇异积分不是逐点算子,它会感受到坏集合附近的空间结构。

    正确做法是看 maximal function 的超水平集:

    $$\Omega=\{x:Mf(x)>\lambda\}.$$

    然后对 $\Omega$ 做 Whitney decomposition,得到一族彼此控制重叠的 cubes 或 balls。

    2. 分解定理

    Calderon-Zygmund 分解给出

    $$f=g+\sum_j b_j,$$

    并且满足:

    $$|g(x)|\lesssim \lambda \quad\text{a.e.},$$

    $$\operatorname{supp} b_j\subset Q_j,\qquad \int b_j=0,$$

    以及

    $$\sum_j |Q_j|\lesssim \frac{\|f\|_1}{\lambda},\qquad \sum_j\|b_j\|_1\lesssim \|f\|_1.$$

    这里的零平均是关键。奇异积分核在远离 $Q_j$ 的地方可以用光滑性做差分估计,从而把 $b_j$ 的大振幅抵消掉。

    3. 用它证明弱 $(1,1)$

    设 $T$ 是 Calderon-Zygmund singular integral,并已知 $T$ 在 $L^2$ 上有界。为了证明

    $$|\{x:|Tf(x)|>\lambda\}|\lesssim \frac{\|f\|_1}{\lambda},$$

    把 $f=g+b$。好部分用 $L^2$ 有界性处理:

    $$|\{|Tg|>\lambda/2\}|\lesssim \lambda^{-2}\|g\|_2^2\lesssim \frac{\|f\|_1}{\lambda}.$$

    坏部分先丢掉扩大后的坏 cubes,它们总体积可控;在外面利用 $\int b_j=0$ 写

    $$Tb_j(x)=\int_{Q_j}\bigl(K(x,y)-K(x,c_j)\bigr)b_j(y)\,dy,$$

    再用 kernel 的 Holder 光滑性求和。

    4. 更广的分解哲学

    Calderon-Zygmund 分解的精神是:在物理空间中识别坏区域,把坏区域局部化,并为每个坏块制造 cancellation。类似思想在 weighted theory、Hardy space、Whitney decomposition、wave packet decomposition 和 polynomial partitioning 中都会出现。

    不同分解保留不同对称性。Calderon-Zygmund 分解突出空间局部性;wave packet 分解同时追踪空间和频率;polynomial partitioning 则把几何 incidence 信息放进分析估计里。调和分析很多证明,本质上都是在寻找适合当前算子的分解方式。

  • Large sieve 与 Bombieri-Vinogradov theorem:几乎正交性的数论形态

    旧博客原文

    原题:The large sieve and the Bombieri-Vinogradov theorem

    -1.Motivation-

    Large sieve a philosophy reflect as a large group of inequalities which is very effective on controlling some linear sum or square sum of some correlation of arithmetic function, some idea of which could have originated in harmonic analysis, merely rely on almost orthogonality.

    One fundamental example is the estimate of the quality,

    \sum_{n\leq x}|\Lambda(n)\overline{\chi(n)}|

    One naive idea of control this quality is using Cauchy-schwarz inequality. But stupid use this we gain something even worse than trivial estimate. In fact by triangle inequality and trivial estimate we gain trivial bound: \sum_{n\leq x}|\Lambda(n)\overline{\chi(n)}|\leq x. But by stupid use Cauchy we get following,

    \sum_{n\leq x}|\Lambda(n)\overline{\chi(n)}|\leq ((\sum_{n\leq x}|\Lambda(n)|^2)(\sum_{n\leq x}|\chi(n)|^2))^{\frac{1}{2}}\leq xlog^{\frac{1}{2}}x

    But this does not mean Cauchy-Schwarz is useless on charge this quality, we careful look at the inequality and try to understand why the bound will be even worse. Every time we successful use Cauchy-Schwarz there are two main phenomenon, first, we lower down the complexity of the quantity we wish to bound, second we almost do not loss any thing at all. So we just reformulate the quantity and find it lower down the complexity and the change is compatible with the equivalent condition of Cauchy-Schwarz. For example we have following identity,

    \sum_{n\leq x}|\Lambda(n)\overline{\chi(n)}|=\sqrt{ \sum_{n\leq x}|\Lambda(n)\overline{\chi(n)}| \sum_{m\leq x}|\Lambda(m)\overline{\chi(m)}|}=\sqrt{ \sum_{k_1,k_2\in \mathbb F_p^{\times}}\sum_{n',m'\leq \frac{x}{p}}|\Lambda(n')\Lambda(m')\overline{\chi(k_1)\chi(k_2)}| }

    So we could understand this quality as the Variation of primes in arithmetic profession constructed by \{pn+b| b\in\{1,2,...,p-1\}\}. But this is still difficult to estimate, merely because of we need to control the variation of convolution of \Lambda with itself on \mathbb F_p^{\times}\simeq \{pn+b| b\in\{1,2,...,p-1\}\}.

    Now we change our perspective, recall a variant of Cauchy-Schwarz inequality, which called Bessel inequality, as following,

    Bessel inequality

    Let {g_1,\dots,g_J: {\bf N} \rightarrow {\bf C}} be finitely supported functions obeying the orthonormality relationship,

    \displaystyle \sum_n g_j(n) \overline{g_{j'}(n)} = 1_{j=j'}

    for all {1 \leq j,j' \leq J}. Then for any function {f: {\bf N} \rightarrow {\bf C}}, we have,

    \displaystyle (\sum_{j=1}^J |\sum_{n} f(n) \overline{g_j(n)}|^2)^{1/2} \leq (\sum_n |f(n)|^2)^{1/2}.

    Pf: The proof is not very difficult, we just need to keep an orthogonal picture in our mind, consider \{g_{j}(n)\}, 1\leq j\leq J to be a orthogonal basis on l^2(\mathbb N), then this inequality is a natural corollary.

    Have this inequality in mind, by the standard argument given by transform from version of orthogonal to almost orthogonal which was merely explained in the previous note.  We could image the following corresponding almost orthogonal variate of “Bessel inequality” is true:

    Generalised Bessel inequality

    Let {g_1,\dots,g_J: {\bf N} \rightarrow {\bf C}} be finitely supported functions, and let {\nu: {\bf N} \rightarrow {\bf R}^+} be a non-negative function. Let {f: {\bf N} \rightarrow {\bf C}} be such that {f} vanishes whenever {\nu} vanishes, we have

    \displaystyle (\sum_{j=1}^J |\sum_{n} f(n) \overline{g_j(n)}|^2)^{1/2} \leq (\sum_n |f(n)|^2 / \nu(n))^{1/2} \times ( \sum_{j=1}^J \sum_{j'=1}^J c_j \overline{c_{j'}} \sum_n \nu(n) g_j(n) \overline{g_{j'}(n)} )^{1/2}

    for some sequence {c_1,\dots,c_J} of complex numbers with {\sum_{j=1}^J |c_j|^2 = 1}, with the convention that {|f(n)|^2/\nu(n)} vanishes whenever {f(n), \nu(n)} both vanish.

     


    补充说明

    以下是新整理的中文说明;上方旧博客原文保持不变。

    Large sieve 是一族控制算术序列在线性相位或剩余类中分布的强大不等式。它的核心精神和调和分析中的 almost orthogonality 非常接近。

    Large sieve 与 Bombieri-Vinogradov theorem:几乎正交性的数论形态
    large sieve 用几乎正交性控制许多模数和 residue phases 上的平方和。

    1. 基本形状

    典型 large sieve inequality 形如

    $$\sum_{q\le Q}\sum_{\substack{a\bmod q\\(a,q)=1}}
    \left|\sum_{n\le N}a_n e(an/q)\right|^2
    \le (N+Q^2)\sum_{n\le N}|a_n|^2.$$

    它说明不同模数和不同 residue phases 之间几乎正交。

    2. 为什么 Cauchy-Schwarz 要小心用

    粗暴使用 Cauchy-Schwarz 可能比平凡估计还差。成功的关键是先把要求的量重写成具有正交结构的平方和,再用 Cauchy-Schwarz 或 Parseval。

    3. 算术级数中的素数

    Bombieri-Vinogradov theorem 控制素数在平均模数意义下的分布:

    $$\sum_{q\le Q}\max_{(a,q)=1}\left|\psi(x;q,a)-\frac{x}{\varphi(q)}\right|$$

    在 $Q\le x^{1/2}$ 附近仍有强估计。它可以看作广义 Riemann hypothesis 在平均意义下的替代。

    4. Large sieve 的作用

    large sieve 给出对字符和指数和的均方控制。结合 Vaughan identity、零点密度估计或双线性分解,可以处理素数在很多模数下的平均误差。

    5. 哲学

    Large sieve 的力量在于:我们不逐个模数证明最优分布,而是在整个模数族上利用几乎正交性。这个思想和调和分析中 square function、wave packet 的平均控制是一脉相承的。

  • 自由群 $F_2$ 上的线性度量:Cayley graph、范数空间与 pullback

    旧博客原文

    原题:Linear metric on F2, free group with two generator.

    img_0515.jpg

    I may have made a stupid mistake, but if not, we could construct a metric by pullback a metric on a suitable linear normalized space H which we carefully constructed. Let we define the generators of free group F_2 by a,b.

    Step 1.

    Constructed the linear normalized space H. the space H was spanned by basis \Lambda=\Lambda_a \coprod \Lambda_b, \Lambda_a, \Lambda_b are defined by look at the Cayley graph of F_2, there is a lot of vertical vector and horizontal vector in the Cayley graph, for every level set of vertical vector we put a basis in \Lambda_a, because there is only countable many vertical vectors (for example, a,a^2,a^{-5} are in the same vertical level, bab^{-1}, ba^{10}b^{-1} are in the same vertical level, bab^{-1},a are not in the same vertical level), we put a basis in \Lambda_a for every vertical level and claim we accomplished the construct of \Lambda_a, we do the same operation for \Lambda_b but only change the vertical level with horizontal level. Now we accomplished the construction of \Lambda, We spanned this with coefficient \mathbb Z and we get a linear space V. by Zorn’s lemma there exists a norm on the space, take one norm \|\cdot\| we accomplished the construction of H=(V,\|\cdot\|).

    Step 2:

    Pullback the norm \|\cdot\| on H to the free group F_2. In fact there is a natural bijection T: F_2\to H, which is given by following: On the Cayley graph (imaged it is embedding in \mathbb R^2), identity 1 in the group F_2 corresponding to the original, and more general every element in F_2 exactly identify with a point in the Cayley graph, thanks to there is no relation between a,b. And then there is of course infinity many of path from original to the point, but there is only one shortest path , thanks to there is no loop in the Cayley graph. We identify the elements in F_2 with the point in Cayley graph with the shortest path. Now we could explain why the path lies H. This path only across to finite vertical level and horizontal level and on every level it only pass finite step, this already given a representation \sum_{e_i\in \Lambda}c_i\cdot e_i, c_i\in \mathbb Z, the key point is there is only finite c_i\neq 0. So we have defined the bijection T:F_2\to H, and we could use the bijection to pullback the norm on H to a norm on F_2.

    Step 3:

    Now we begin to proof the norm we get by pullback satisfied the condition we need. We need only to proof the condition of linear growth and triangle inequality. The conjugation invariance is automatically by linear growth by the comments of Tobias Fritz. The triangle inequality is automatically, due to the bijection T stay the structure in fact, the multiplier of elements x_1,x_2 \in_2 could be view as put the two path together but this  is not true… merely because of the addition operation is not commutative.

    The space we should consider is the path space equipped with the composition operation. I image there exists a “big space” such that the natural metric on the “big space” restrict on the embedding image of \mathbb F_2 is a linear growth metric.


    补充说明

    以下是新整理的中文说明;上方旧博客原文保持不变。

    自由群 $F_2=\langle a,b\rangle$ 的 Cayley graph 是一棵正则树。一个自然想法是:能否把这棵树嵌入某个线性赋范空间,然后把范数距离 pull back 回群上,得到一种由线性构造出来的 metric?

    自由群 $F_2$ 上的线性度量:Cayley graph、范数空间与 pullback
    自由群的 Cayley graph 是树,把它映到赋范空间后可以 pull back 得到由线性构造出来的 metric。

    1. Cayley graph 图像

    $F_2$ 的每个元素都是一个约化字。Cayley graph 的顶点是群元素,边对应左乘或右乘生成元。因为自由群没有非平凡关系,这个图没有环,是一棵树。

    2. 从边方向构造线性空间

    可以尝试给 Cayley tree 中不同“水平”的水平边、垂直边分配基向量。设这些基张成一个向量空间 $V$,再在 $V$ 上选择一个范数 $\|\cdot\|$。

    每个群元素对应从单位元到该点的唯一 geodesic path,于是可把路径上的边向量相加,得到映射

    $$\Phi:F_2\to V.$$

    3. Pullback metric

    定义

    $$d(g,h)=\|\Phi(g)-\Phi(h)\|.$$

    如果 $\Phi$ 是单射,这确实给出 metric。若范数选得合适,它可能与 word metric 有可比较关系;若选得太退化,则会丢失树的几何。

    4. 需要注意的问题

    真正困难在于,这种构造是否自然、是否左不变、是否 quasi-isometric 于 word metric。普通 word metric 满足

    $$d_S(g,h)=|g^{-1}h|_S,$$

    具有明显的左不变性;pullback metric 未必自动保留这个性质。

    5. 几何意义

    这个问题可以看作自由群嵌入 Banach space 的 toy model。它连接 Cayley graph、tree metric、coarse embedding 和 geometric group theory 中的线性化思想。

  • Almost orthogonality:Cotlar-Stein lemma、Schur test 与奇异积分

    旧博客原文

    原题:Almost orthogonality

     

    Motivation and Cotlar’s lemma

    We always need to consider a transform T on Hilbert space l^2(\mathbb Z) (this is a discrete model), or a finite dimensional space V. If under a basis T is given by a diagonal matrix this story is easy,

    \displaystyle A = \begin{pmatrix} \Lambda_1 & 0 & \ldots & 0 \\ 0 & \Lambda_2 & \ldots & 0 \\ \vdots & \vdots & \ddots & \vdots \\ 0 & 0 & \ldots & \Lambda_n \end{pmatrix} \ \ \ \ \ (5)

    Then ||T||=\max_{i}\lambda_i.

    In fact, for T is a transform of a finite dimensional space, T is given by (a_{ij})_{n\times n} by duality we have ||T||=||TT^*||, so we have,

    ||T||=||TT^*||=|(\sum a_{ij}x_j)y_i|\leq |\sum_{i,j}\frac{1}{2}(|a_{ij}(|x_i|^2+|y_j|^2)|\leq M

    If we have given \sum_{i}|a_{ij}|\leq M and \sum_{j}|a_{ij}|\leq M \forall i,j\in \{1,2,...,n\}.

    But in application of this idea, the orthogonal condition always seems to be too restricted and due too this we have the following lemma which is follow the idea but change the orthogonal condition by almost orthogonal.

    Lemma(Catlar-Stein)

    Let \{T_j\}_{j=1}^N be finitely many operators on some Hilbert space H. Such that for some function \gamma : \mathbb Z\to R^+ one has,

    ||T_j^*T_k||\leq \gamma^2(j-k),||T_jT_k^*||\leq \gamma^2(j-k)

    for any 1\leq j,k\leq N. Let \sum_{l=-\infty}^{\infty}\gamma(l)=A<\infty. then ,

    ||\sum_{j=1}^NT_j||\leq A

    Pf:

    tensor power trick + duality ||T||=||TT^*||^{\frac{1}{2}}.

    Singular integrals on L^2

     

    Lemma(Schur)

    Define T is a operator on measure space X\times Y equipped positive product measure \mu\wedge \nu, via,

    (Tf)(x)=\int_YK(x,y)f(y)\nu(dy)

    K is a measurable kernel, then,

    1). ||T||_{1\to 1}\leq \sup_{y\in Y}\int_{X}|K(x,y)|\mu(dx)=:A.

    2). ||T||_{\infty\to \infty}\leq \sup_{x\in X}\int_{Y}|K(x,y)|\nu(dy)=:B.

    3). ||T||_{p\to p}\leq A^{\frac{1}{p}}B^{\frac{1}{p'}},  \forall 1\leq p\leq \infty.

    4). ||T||_{1\to \infty}\leq ||K||_{L^{\infty}(X\times Y)}.

    Pf:

    1),2),4) merely due to Fubini theorem and Bath lemma.

     

    3) proof by the interpolation and combine 1) and 2).

    Theorem

    Let K be a Calderon-Zegmund operator, with the additional assumption

    that |\nabla K(x)|\leq B|x|^{-d-1}. Then

    ||T||_{2\to 2} \leq CB

    with C = C(d).

    Caldero ́n–Vaillancourt theorem

     

    Hardy’s inequality

    Theorem(Hardy inequality)

    For any 0 \leq s < \frac{d}{2} there is a constant C(s, d) with the prop-

    arty that,

    |||x|^{-s} f||_2 \leq C(s,d)||f||_{H^s(R^d)}

    for all f \in H^s(R^d).

     


    补充说明

    以下是新整理的中文说明;上方旧博客原文保持不变。

    正交性是 Hilbert space 中最强的简化机制;almost orthogonality 则是在真实分析问题中更常见的替代品。频率块、空间块和算子族通常不完全正交,但交互足够小。

    Almost orthogonality:Cotlar-Stein lemma、Schur test 与奇异积分
    almost orthogonality 用交互衰减替代严格正交,是奇异积分和伪微分算子估计的基础。

    1. 从正交到几乎正交

    若 $T_j$ 的像彼此正交,则

    $$\left\|\sum_j T_j f\right\|_2^2=\sum_j\|T_jf\|_2^2.$$

    实际中通常只有 $T_i^\ast T_j$ 和 $T_iT_j^\ast$ 随 $|i-j|$ 衰减。

    2. Cotlar-Stein lemma

    $$\|T_i^\ast T_j\|+\|T_iT_j^\ast\|\le a(i-j)$$

    且 $\sum_k a(k)^{1/2}<\infty$,则

    $$\left\|\sum_jT_j\right\|_{2\to2}<\infty.$$

    证明可用 tensor power trick 和对偶性。

    3. Schur test

    对 kernel operator

    $$Tf(x)=\int K(x,y)f(y)\,dy,$$

    $$\sup_x\int |K(x,y)|dy<\infty,\qquad \sup_y\int |K(x,y)|dx<\infty,$$

    则 $T$ 在 $L^2$ 上有界。

    4. 奇异积分中的用途

    Calderon-Zygmund theory 中,常把算子分解成不同尺度的 pieces。尺度相隔很远时,kernel 的光滑性带来交互衰减;相近尺度则只需有限重叠。

    5. Calderon-Vaillancourt 方向

    伪微分算子的 $L^2$ 有界性也可以看成 almost orthogonality 的结果:把相空间切成小块后,不同块之间的交互由 symbol 的导数控制。

  • 短区间中 Mobius 函数与 nil-sequence 的相关估计

    旧博客原文

    原题:The correlation of Mobius function and nil-sequences in short interval

    I wish to establish the following estimate:

    Conjecture :(correlation of Mobius function and nil-sequences in short interval)

    \lambda(n) is the liouville function we wish the following estimate is true.

    \int_{0\leq x\leq X}|\sup_{f\in \Omega^m}\sum_{x\leq n\leq x+H}\lambda(n)e^{2\pi if(x)}|dx =o(XH).

    Where we have H\to \infty as x\to \infty, \Omega^m=\{a_mx^m+a_{m-1}x^{m-1}+...+a_1x+a_0 | a_m,...,a_1,a_0\in [0,1]\} is a compact space.

    I do not know how to prove this but this is result is valuable to consider, because by a Fourier identity we could transform the difficulty of (log average) Chowla conjecture to this type of result.

    There is some clue to show this type of result could be true, the first one is the result established by Matomaki and Raziwill in 2015:

    Theorem (multiplication function in short interval)

    f(n): \mathbb N\to \mathbb C is a multiplicative function, i.e. f(mn)=f(n)f(m), \forall m,n\in \mathbb N. H\to \infty as x\to infty, then we have the following result,

    \int_{1\leq x\leq X}|\sum_{x\leq n\leq x+H}f(n)|=o(XH).

    And there also exists the result which could be established by Vinagrodov estimate and B-S-Z critation :

    Theorem(correlation of multiplication function and nil-sequences in long interval)

    f(n): \mathbb N\to \mathbb C is a multiplicative function, i.e. f(mn)=f(n)f(m), \forall m,n\in \mathbb N. g(n)=a_n^m+...+a_1n+a_0 is a polynomial function then we have the following result,

    \int_{1\leq n \leq X}|f(n)e^{2\pi i g(n)}|=o(X).


    补充说明

    以下是新整理的中文说明;上方旧博客原文保持不变。

    希望建立的估计可以粗略写成:对 Liouville 函数或 Mobius 函数 $\lambda(n)$,以及复杂度受控的 nil-sequence $F(g^n x)$,在短区间 $I=[X,X+H]$ 上有

    $$\frac1H\sum_{n\in I}\lambda(n)F(g^n x)=o(1).$$

    这里 $H=H(X)\to\infty$,但 $H$ 可以远小于 $X$。这类估计如果成立,会把短区间乘法函数理论和 Sarnak/Chowla 型问题连接起来。

    短区间中 Mobius 函数与 nil-sequence 的相关估计
    短区间中的 Mobius-nilsequence 相关估计试图在局部窗口内捕捉乘法函数的随机性。

    1. 为什么是 nil-sequence

    nil-sequence 是低复杂度动力系统轨道的模型。多项式相位 $e(P(n))$ 是最基本例子,更高阶 nilmanifold 上的轨道则对应高阶 Fourier 分析中的结构部分。若 Mobius 与所有这类低复杂度序列正交,就说明它在动力系统意义下表现得像随机噪声。

    2. 短区间困难

    长区间中可以使用 Bourgain-Sarnak-Ziegler criterion、Vinogradov 型估计和 nilsequence equidistribution。短区间的问题更硬,因为平均长度不够,许多全局消去无法直接使用。

    Matomaki-Radziwill 的定理说明,乘法函数在几乎所有短区间中仍有平均消去。这给出一个强烈信号:如果 nil-sequence 的结构在短窗口上足够规则,那么相关和也应当消失。

    3. 与 Chowla 的关系

    对数平均 Chowla 猜想可以通过 Fourier 展开和结构分解,转化为乘法函数与低复杂度序列的相关估计。这里的短区间版本相当于把“全局随机性”压缩到局部窗口中观察。

    4. 可能路线

    一个可行框架是:先用短区间乘法函数定理处理非结构部分,再对 nil-orbit 做定量 equidistribution 分解,最后用 BSZ 型准则控制剩余相关。核心瓶颈是所有常数都必须对短区间长度 $H$ 有足够好的依赖。

  • 一个 Fourier 系数衰减估计:解析延拓、分歧提升与矩阵值函数

    旧博客原文

    原题:An Fourier coefficient decay estimate.

    f is a matrix value analytic function on \mathbb T, we know h(f)>\alpha, this is just mean \forall k\in \mathbb Z , assume | \hat f(k)|\leq e^{-|k|\alpha} , g=log(f) for which we assume g is a lifting of f use the inverse of ramification map ,

    M_{n\times n} \to M_{n\times n} , A \to e^A.

    Then exists \beta=c(\alpha)>0 such that ,

    \forall k \in \mathbb Z, |\hat g(k)| \leq e^{-k\beta}.


    补充说明

    以下是新整理的中文说明;上方旧博客原文保持不变。

    设 $f$ 是圆周或环面上的矩阵值解析函数。解析性最直接的 Fourier 后果是指数衰减:

    $$\|\widehat f(k)\|\le C e^{-\rho |k|}.$$

    这里 $\rho$ 不是一个装饰性常数,而是由 $f$ 能延拓到多宽的复邻域决定。若函数还经过分歧映射的提升,衰减率会被分歧阶数重新缩放。

    一个 Fourier 系数衰减估计:解析延拓、分歧提升与矩阵值函数
    解析函数的 Fourier 系数指数衰减,衰减率由复邻域宽度和可能的分歧提升共同决定。

    1. 一维解析情形

    如果 $f$ 在带状区域 $|\operatorname{Im} z|<\rho$ 内解析且有界,那么

    $$\widehat f(k)=\int_0^1 f(x)e^{-2\pi i kx}\,dx.$$

    当 $k>0$ 时把积分路径向上平移 $i\sigma$,得到因子 $e^{-2\pi k\sigma}$;当 $k<0$ 时向下平移。令 $\sigma<\rho$,就得到指数衰减。

    2. 矩阵值函数没有本质困难

    若 $f(x)$ 取值于矩阵空间,只需要把绝对值换成任意相容矩阵范数。Cauchy 积分和路径平移仍逐项成立,因此

    $$\|\widehat f(k)\|\le \sup_{|\operatorname{Im}z|\le\sigma}\|f(z)\|\,e^{-2\pi\sigma |k|}.$$

    3. 分歧提升的影响

    若 $f$ 通过某个 ramification map 被提升,例如局部写成 $z=w^m$,那么 $w$ 平面中的解析带宽会按比例改变。直观上,绕分歧点一圈的角变量被拉伸,Fourier 频率也随之重标定。

    4. 估计的用途

    这类估计常出现在解析 cocycle、准周期系统和小除数问题中。指数衰减提供了“高频很小”的精确版本,使得截断 Fourier 级数时可以把尾项压到可控范围。

  • 非线性椭圆方程平均值性质的几何直觉

    旧博客原文

    原题:Geometric intuition of mean value property of nonlinear elliptic equation

    I wish to gain some understanding of the MVP of nonlinear elliptic equation by geometric intuition.

     

    Linear elliptic equation case

    First of all, I have a very good geometric explain of the MVP of Laplace equation, i.e.

    MVP of laplace equation

    \Delta u=0 in \Omega , \forall B(x_0,r)\subset \Omega is a Ball, we have following identity:

    \frac{1}{\mu(\partial(B))}\int_{\partial B}u(x)dx=u(x_0)

     

    I need to point out first, this property is not difficult to proof by standard integral by part method, but the following method have more geometric intuition. And in some sense explain why this property holds.

    The proof is not very difficult to explain by mathematic formula, but I wish to divide the proof into two part, explain one part by graph and literal interpretation.

    part 1 of the proof:

    we consider a 1-parameter group of foliation, and consider the integral identity with this foliation.

    \int_{v\in S_{n-1}}\int_{\gamma_v} \frac{\partial \partial_{v}u}{\partial t}dt=\int_{B(x_0,r)}\partial_{n}u-\int_{S_{n-1}}\partial_{v}udv=\int_{B(x_0,r)}\partial_{n}u

    Part 2 of the proof:

    and we have:

      \int_{v\in S_{n-1}}\int_{\gamma_v} \frac{\partial \partial_{v}u}{\partial t}dt=0

    by the pointwise equation \Delta u=0, one key point is \partial_{-v-v}u=\partial_{vv}u, \forall v\in S_{n-1}.

     

    This approach cloud easily to transform to the general elliptic equation case and it seems a little difficult to transform to Possion equation, the non-hemomorphism case.

     

    Nonlinear elliptic equation case

     

    A-B-P estimate for general nonlinear uniformly elliptic equation

     

    ABP estimate is the most basic estimate in fully nonliear elliptic equation.
    The ABP maximum principle states (roughly) that, if

    a^{ij} \partial _i \partial _j u \geq f, in \ \Omega \subset \mathbb{R}^n (a^{ij} \geq C Id >0),

    Then (assuming sufficient regularity of the coefficients),

    \sup _{\Omega} u \leq \sup _{\partial \Omega} u + C (\int _{\Omega} \vert f \vert^n )^{1/n} ………. (*)

    I will give an intuitive explanation of the proof of (*) .
    Usually, in order to prove maximum principles, the key idea is to use that at a local max the second derivative is negative-definite, then choose a good basis and get some identity of 1-order drivative and inequality for 2-order’s. This process is used in such like the proof of the Hopf lemma, and some inter gradient estimate, consider some flexiable function like e^{Au} or sometihng else anyway.

    But in the proof of ABP we need more geometric intution and more trick.

    First we do a rescaling:
    if a^{ij} \partial _i \partial _j u \geq 1, in B_1 \subset \mathbb{R}^n (a^{ij} \geq C Id >0),u|_{\partial B_1}\geq 0.
    then:

    |inf_{B_1}u| \leq C |A|^{1/n} ....(**)

    And then We explain what is the contact set. It is the subset \Gamma^{+} of \Omega such that u agree with it convex envelop. i.e. \Gamma^{+}=\{x|u=convex \ evolap \ of \ u\ at \ x\} . The geometric meaning is it has at least one lower support plane. So what is \Gamma^{+} it is just the set that u is very low on it. Or in another way of view you consider -u as a lot of mountains then \Gamma^+ is the place near the tops of which mountain can see every thing (locally).
    Then we look at every point in \Gamma^{+} , then determination of the hessian matrix det(u_{ij}) at this point have a control due to the PDE a^{ij} \partial _i \partial _j u \geq 1, and the uniformly elliptic property.

    The determination of hessian matrix could be view as a determination of Jacobe matrix of the map (u_1,...,u_n)\to (e_1,...,e_n) .and by Area formula we have:

    \int_{\Phi(\Omega)}  f( \Phi^{-1}(y)) dy =\int_{\Omega}f(x)|J({\Phi(x)})| dx,

    It is easy to see for a constant c ,B_{c|sup_{\Omega}|u||}(0)\subset \Phi(\Omega) (Base on the PDE on every point, the geometric intution is just the function u could not be very narrow cone at every point). So we have , take f=\chi_{\Gamma^{+}} ,

    |B_{c\sup_{\Omega}|u|}(0)|^{n}\leq \int_{\Gamma^{+}}\chi_{\Gamma_{+}}(x)|J_{\Phi}(x)|dx

    so we have:

    |B_{c\sup_{\Omega}|u|}(0)|\lesssim |{\Gamma_{+}}|^{\frac{1}{n}}...(***)

    and the classical matrix inequality for every positive definite matrix A we have
    :

    det(AB)\leq (\frac{tr(AB)}{n})^n...(****) .

    combine (***),(****) ,we have:

    sup_{\Omega}|u|\lesssim ||\frac{a^{ij}u_{ij}}{D^*}||_{L^n({\Gamma^+})} .

     

    graph

    General approach to get MVP for elliptic equation which is come from geometry

     

    MVP for K-hessian equation, with geometric explanation

     

    MVP for K-curvature equation, with geometric explanation 

     

    MVP for p-Laplace equation, with geometric explanation

     

     

     


    补充说明

    以下是新整理的中文说明;上方旧博客原文保持不变。

    调和函数的平均值性质是椭圆方程最漂亮的几何现象之一。在线性情形,它来自球面对称和分部积分;在非线性椭圆方程中,真正的替代物往往不是严格平均值公式,而是 ABP estimate、contact set 和凸包几何。

    非线性椭圆方程平均值性质的几何直觉
    线性调和函数有球面平均值性质,非线性椭圆方程则用 ABP estimate 和接触集合几何替代。

    1. Laplace 方程的平均值性质

    若 $\Delta u=0$,则对球 $B_r(x)$,

    $$u(x)=\frac1{|\partial B_r|}\int_{\partial B_r(x)}u\,d\sigma.$$

    证明可用 Green identity,也可以看成沿同心球 foliation 的通量守恒。

    2. 几何解释

    $$A(r)=\frac1{|\partial B_r|}\int_{\partial B_r(x)}u.$$

    对 $r$ 求导后,$\Delta u=0$ 让通量项消失,于是 $A(r)$ 为常数。球面对称和散度结构共同产生平均值性质。

    3. 非线性情形的问题

    对一般 fully nonlinear elliptic equation

    $$F(D^2u,x)=f,$$

    没有线性叠加,也没有简单的球面平均公式。我们需要用比较原理和接触几何替代平均值。

    4. ABP estimate

    ABP 最大值原理粗略地说给出

    $$\sup_\Omega u\le \sup_{\partial\Omega}u+C\|f\|_{L^n(\Omega)}.$$

    其证明看 $u$ 的凸包和 contact set。梯度映射的面积公式把函数的最大值和右端 $f$ 的积分联系起来。

    5. 一条直觉

    线性平均值性质说:每个点由周围平均决定。非线性椭圆理论说:最大值由接触集合和 Monge-Ampere 型几何控制。二者背后的共同点是椭圆性阻止信息沿单一方向集中,迫使解受到周围区域的整体约束。

  • 代数数的 Diophantine approximation:Liouville、Roth 与 Vandermonde 约束

    旧博客原文

    原题:Diophantine approximation of algebraic number

    An important theorem in Diophantine approximation is the theorem of Liuoville:

    **Liuoville Theorem** If x is a algebraic number of degree n over the rational number then there exists a constant c(x) > 0 such that:\left|x-{\frac {p}{q}}\right|>{\frac {c(x)}{q^{{n}}}}

    holds for every integer p,q\in N^* where q>0.

    This theorem explain a phenomenon, the approximation of algebraic number by rational number could not be very well. Which was generated later to **Thue–Siegel–Roth theorem**, them could be used to proof a lots of constant is not algebraic, i.e. transcendentals .

    My questions is in another direction, now let us not just consider one root  \alpha_1 of a integer polynomial P(x)=a_mx^m+...+a_1x+a_0 but consider all roots of it, i.e. \{\alpha_1,...,\alpha_m\}, which is based on a observation : If we define

    \sigma_k(P(x))=\sum_{1\leq \alpha_{i_1}<\alpha_{i_2}<...<\alpha_{i_k}\leq m}\alpha_{i_1}\alpha_{i_2}...\alpha_{i_k}

    By **Vieta theorem** we know \sigma_k(n)\in \mathbb Q for all k\in N^*, this will lead to some restriction and in fact destroy the uniformly distribution of (\alpha_1,...,\alpha_m)\in [0,1]^m. In fact the most important one is the determination of Vandermon Determinant:
    V(P(x))=\Pi_{1\leq \alpha_i<\alpha_j\leq m}(\alpha_i-\alpha_j).

    We know \Pi_{1\leq \alpha_i<\alpha_j\leq m}(\alpha_i-\alpha_j)\in \mathbb Q so when \Pi_{1\leq \alpha_i<\alpha_j\leq m}(\alpha_i-\alpha_j)\neq 0 we could use this to proof a nontrivial estimate for \sum_{1\leq k\leq m}||\alpha_kn||_{\mathbb R/\mathbb Z}.
    \sum_{1\leq k\leq m}||\alpha_kn||_{\mathbb R/\mathbb Z}= O(\frac{1}{n^{\frac{1}{m-1}}}).

    by combine the A-G inequality and \Pi_{1\leq \alpha_i<\alpha_j\leq n}(\alpha_i-\alpha_j)=\lambda\neq 0.While by continue fractional expansion we only know a trivial estimate of type \sum_{1\leq k\leq m}||\alpha_kn||_{\mathbb R/\mathbb Z}= O(\frac{1}{n}).

    my question is the following:
    Is there still have a nontrivial estimate for \sum_{1\leq k\leq m}||\alpha_kn||_{\mathbb R/\mathbb Z} (which could be slight weaker), if we don’t have the whole power of **Vieta theorem**? more precisely:

    **problem 1**

    if we have \sigma_k((\alpha_1,...,\alpha_m))=\lambda_k\in \mathbb Q for all k\in \{1,2,...,m'\} where m'<m, is there still some nontrivial estimate of,

    \sum_{1\leq k\leq m}||\alpha_kn||_{\mathbb R/\mathbb Z}

    hold for all n\in N^*?

    One reason to consider this could be true is that although \{\alpha_1,...,\alpha_m\} is not roots of a integer polynomial but we could image in some suitable metric space X the gromov-hausdorff distance of tuple (\alpha_1,...,\alpha_m) and a tuple come form roots of integer polynomial is small . And it seems reasonable to image this type of asymptotic quality is continue with the G-H distance on X.

    Another problem is what happen when V((\alpha_1,...,\alpha_m))=\Pi_{1\leq i<j\leq n}(\alpha_i-\alpha_j)=0. More precisely,

    **problem 2**

    What happen when V((\alpha_1,...,\alpha_m))=\Pi_{1\leq i<j\leq n}(\alpha_i-\alpha_j)=0 , is this result,

    \sum_{1\leq k\leq m}||\alpha_kn||_{\mathbb R/\mathbb Z}= O(\frac{1}{n^{\frac{1}{m-1}}}).

    still true?

    Let us go a litter further, if these two problem both have a satisfied answer, what is the higher dimensional case?

    **problem 3**

    Given m\in \mathbb N^*. If tuple (y_1,...,y_k) is very closed to the zero set of a variety in \mathbb Z[x_1,...,x_m] in \mathbb (Z^{m})^k in the sense a lots of symmetric sum of y_1,...,y_k belong to \mathbb Q^m, will this lead to some good estimate for

    \sum_{1\leq s\leq k}||y_sn||_{\mathbb R^m/\mathbb Z^m}?

    I think these type of result should be investigated very well, Iappreciate to any pointer with useful comments and answer, both on given some strategy to solve these problems or given some reference about these problems.


    补充说明

    以下是新整理的中文说明;上方旧博客原文保持不变。

    代数数不能被有理数“过分好”地逼近。Liouville theorem 是这件事的第一层形式,Thue-Siegel-Roth theorem 则给出几乎最优的结论。

    代数数的 Diophantine approximation:Liouville、Roth 与 Vandermonde 约束
    Liouville 和 Roth 定理说明代数数不能被有理数过分好地逼近。

    1. Liouville theorem

    若 $\alpha$ 是次数 $d$ 的代数数,则存在 $C(\alpha)>0$,使对所有有理数 $p/q$,

    $$\left|\alpha-\frac pq\right|\ge \frac{C(\alpha)}{q^d}.$$

    证明的核心是把 $\alpha$ 代入整数多项式 $P$,再估计 $P(p/q)$ 不可能是太小的非零有理数。

    2. Roth theorem

    Roth theorem 大幅加强 Liouville:若 $\alpha$ 是无理代数数,则对任意 $\varepsilon>0$,

    $$\left|\alpha-\frac pq\right|<\frac1{q^{2+\varepsilon}}$$

    只有有限多个有理解。换句话说,代数数的有理逼近指数不能超过 $2$ 太多。

    3. 多个根的约束

    若考虑一个整数多项式的所有根 $\alpha_1,\ldots,\alpha_d$,Vieta 定理给出系数与根的对称函数之间的整数关系。Vandermonde determinant

    $$\prod_{i

    又控制根之间不能全部过分靠近。

    4. 从单点逼近到整体结构

    单个根的有理逼近只看一个 $\alpha$;所有根一起看时,还会出现判别式、对称多项式和高度的约束。整体代数结构比单个连分数展开更刚性。

    5. 一个自然问题

    如果没有完整 Vieta 结构,只知道某些弱的对称约束,是否仍能推出非平凡逼近下界?这类问题位于 Diophantine approximation、代数高度和几何不等式之间。